Respuesta :

Lyu
345 NH3 in moles is: 20.2577490294015 moles.
m(NH₃)=345 g

M(NH₃)=A(N)+3A(H)
M(NH₃)=14.0+3·1.0=17.0g/mol

n(NH₃)=m(NH₃)/M(NH₃)

n(NH₃)=345g/17.0g/mol=20.3 mol